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=-5Y^2-50Y+8
We move all terms to the left:
-(-5Y^2-50Y+8)=0
We get rid of parentheses
5Y^2+50Y-8=0
a = 5; b = 50; c = -8;
Δ = b2-4ac
Δ = 502-4·5·(-8)
Δ = 2660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2660}=\sqrt{4*665}=\sqrt{4}*\sqrt{665}=2\sqrt{665}$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-2\sqrt{665}}{2*5}=\frac{-50-2\sqrt{665}}{10} $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+2\sqrt{665}}{2*5}=\frac{-50+2\sqrt{665}}{10} $
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